IF THE COMPOUND PKA IS 5.3 WHY WE ARE ADJUSTING PH+/-2 OF
THE COMPOUNDS PKA. WHAT IS THE CONDITION
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pKa=pH+log [un ionised]/[ionised]
at the half neutralisation point
un ionised concentration= ionised concentration
so pKa=pH+log1
pKa=pH because log1=0
if we didnt adjudt pH +/-2.0 we may get peak split because
for un ionised we get one peak and ionised we get one more
peak
| Is This Answer Correct ? | 3 Yes | 1 No |
pKa=pH+log [un ionised]/[ionised]
at the half neutralisation point
un ionised concentration= ionised concentration
so pKa=pH+log1
pKa=pH because log1=0
if we didnt adjudt pH +/-2.0 we may get peak split because
for un ionised we get one peak and ionised we get one more
peak
| Is This Answer Correct ? | 1 Yes | 2 No |
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