struct node
{
int *a;
char *b;
char array[12];
};
struct node m,*n;
assign the value in *a,*b,char array[12]
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Answer / varun
m.a=(int*)malloc(4);
*(m.a)=2;
m.b=(char*)malloc(10);
m.b="hello";
strcpy(m.array,"world");
n=(struct node*)malloc(sizeof(struct node));
n->a=(int*)malloc(4);
*(n->a)=2;
n->b=(char*)malloc(10);
n->b="hello";
strcpy(n->array,"world");
Is This Answer Correct ? | 1 Yes | 0 No |
Answer / aravind
struct node
{
int *a;
char *b;
char array[12];
};
struct node m,*n;
m->a*=5;
m->*b='c';
m.array[12]={"aravind");
Is This Answer Correct ? | 1 Yes | 2 No |
/* hello i am ricky dobriyal */
struct node
{
int *a;
char *b;
char array[12];
};
struct node m,*n;
n->a=10;
n->b='5';
m.array="ricky dobriyal";
Is This Answer Correct ? | 0 Yes | 2 No |
what is the advantage of using SEMAPHORES to ORDINARY VARIABLES???
You have given 2 array. You need to find whether they will create the same BST or not. For example: Array1:10 5 20 15 30 Array2:10 20 15 30 5 Result: True Array1:10 5 20 15 30 Array2:10 15 20 30 5 Result: False One Approach is Pretty Clear by creating BST O(nlogn) then checking two tree for identical O(N) overall O(nlogn) ..we need there exist O(N) Time & O(1) Space also without extra space .Algorithm ?? DevoCoder guest Posted 3 months ago # #define true 1 #define false 0 int check(int a1[],int a2[],int n1,int n2) { int i; //n1 size of array a1[] and n2 size of a2[] if(n1!=n2) return false; //n1 and n2 must be same for(i=0;i<n1-1;i++) { if( !( (a1[i]>a1[i+1]) && (a2[i]>a2[i+1]) ) ) return false; } return true;//assumed that each array doesn't contain duplicate elements in themshelves }
2) Write a program that will help Air Traffic Control for an airport to view the sequence of flights ready for take-off. The airport can accommodate 10 flights waiting for take-off at any point in time. Each flight has a unique 3 digit numeric identifier.  Each time a flight takes-off, Air Traffic Control adds a flight to the waitlist. Each time a flight is added to the waitlist, the list of flights waiting to take-off must be displayed.  When a flight is cleared for take-off, Air Traffic Control removes the flight from the waitlist. Each time a flight takes-off, the list of flights waiting to take-off must be displayed.  Sequence of take-off is the sequence of addition to the waitlist
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#include<stdio.h> #include<conio.h> # define swap(a,b) temp=a; a=b; b=temp; void main( ) { int i, j, temp; i=5; j=10; temp=0; if( i > j) swap( i, j ); printf( "%d %d %d", i, j, temp); }
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