Answer / dranav

In electromagnetic flow meter the process flow fluid shall
be conductive like water.

what is the cast iron grade of composition of c-3.06% , Mn- 0.48% , Si-2.38% , S-0.088% , P-0.092% , Cr-0.12% , Ni- 0.012% , Mo-0.00%

0 Answers   L&T,

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Can large temperature differences in vaporizers cause operational problems?

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Whal will be the HRC fuse rating of a 3phase 415V,50Hz,0.85pf,95%efficiency,30KW,1450rpm induction motor,starting with a DOL starter.and describe the Fuse rating calculation.

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In case of welded vessels why is stress relieving in the form of post-weld treatment necessary?

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Thyristor related applications

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dear sir/madam, I had applied for the post of officer trainee so plz if u have any papers both technical or aptitude plz inform me on sonalichavan01@gmail.com

0 Answers   HPCL,

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How can you separate hydrogen peroxide into hydrogen and oxygen?

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PETROLEUM ENGINEERING - QUESTION 25.2 : (a) The American Petroleum Institute gravity, or API gravity, is a measure of how heavy or light a petroleum liquid is compared to water. Let SG = specific gravity of petroleum liquid, and V = barrels of crude oil per metric ton. Given the formula for API gravity = 141.5 / SG - 131.5 and V = (API gravity + 131.5) / (141.5 x 0.159), find the relationship of SG as a function of V. (b) An oil barrel is about 159 litres. If a cylinder with diameter d = 50 cm and height h = 50 cm is used to contain the oil, find the volume V of the cylinder in the unit of oil barrel by using the formula V = 3.142 x d x h x d / 4. (c) First reference : 1 cubic metre = 6.2898 oil barrels. Second reference : 1 cubic metre = 6.37 oil barrels. What are the 2 factors that cause the difference in such reference data?

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What is a good source of surfactant information on the internet?

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need the type of technical questions in written test

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which reformer efficiencywise best?

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In a triple effect evaporator, the heat transfer for an evaporator is calculated as q = UA (TI – TF) where TI is the initial temperature, TF is the final temperature; U and A are constants. Given that heat transfer for the first evaporator : q(1) = UA (TI – TB); second evaporator : q(2) = UA (TB – TC); third evaporator : q(3) = UA (TC – TF) where q(x) is the heat transfer function, TB is the temperature of second inlet and TC is the temperature of third inlet, prove that the overall heat transfer Q = q(1) q(2) q(3) = UA (TI – TF).

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