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how to print a numbers from 1 to 100 with out using control
structures?
- 4 Answers
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Answer / gayitri91
import java.io.*;
class Sample
{
public void printTo100(){
int[] array = new int[101];
try{
printToArrayLimit(array, 1);
}catch(ArrayIndexOutOfBoundsException e){
}
}
public void printToArrayLimit(int array[] , int index){
array[index] = array[index-1]+1;
System.out.println(array[index]);
printToArrayLimit(array, index+1);
}
public static void main(String ar[])
{
Sample s=new Sample();
s.printTo100();
}
}
| Is This Answer Correct ? | 13 Yes | 0 No |
Answer / vinodh
public class Printnos
{
static int a[]=new int[100];
static int i=1;
public static void main(String args[])
{
try
{
i=add(i);
a[i]=i;
main(args);
}
catch(ArrayIndexOutOfBoundsException e){
System.out.println(i);
}
}
static int add(int i)
{
System.out.println(i);
return ++i;
}
}
| Is This Answer Correct ? | 2 Yes | 0 No |
Answer / friend
int i = 1;
System.out.println(i++);
System.out.println(i++);
System.out.println(i++);
System.out.println(i++);
System.out.println(i++);
....................
......................
..................
................
| Is This Answer Correct ? | 7 Yes | 6 No |
Answer / sushila
public class Arr
{
static int a[]=new int[100];
static int i=0;
public static void main(String args[])
{
try
{
i=add(i);
a[i]=i;
main(args);
}
catch(ArrayIndexOutOfBoundsException e){
}
}
static int add(int i)
{
System.out.println(++i);
return ++i;
}
}
| Is This Answer Correct ? | 2 Yes | 1 No |
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