how to calculate material balnce & energy balnce
Answers were Sorted based on User's Feedback
Answer / satishchemeng
By applying Law of conservation of Mass & Law of
conservation of energy to the system we can calculate
Material & Energy balance
| Is This Answer Correct ? | 36 Yes | 2 No |
Answer / rajesh kumar bhagat
By using conservation of mass and energy equation.
| Is This Answer Correct ? | 10 Yes | 1 No |
Answer / kgk kishore
Both can be calculated from the law of conservation of mass
and energy. Since Input whatever we give must come out,
above said formula can be applied in both the cases.
Input- output+ generation = Accumulation.
| Is This Answer Correct ? | 12 Yes | 4 No |
Answer / mahesh ritapure
by using law of mass and energy equetion
| Is This Answer Correct ? | 4 Yes | 1 No |
Answer / jyotsna s.dudhapachare
Material Balnce = Input - out put + Acumulation + Gneration
| Is This Answer Correct ? | 7 Yes | 15 No |
MY generator water cooler inlet line height - 11 mtr inlet water line height - 7 mtr water come into the line from overhead tank, O/H tank height - 20 mtr the first tapping in the inlet line is 2" line which down to 4 mtr level plateform., second tapping in inlet water line goes to a pump 6" line installed at 4 mtr level plateform, pump capacity 200m3/hr, head- 30 mtr, hp-40. the outlet of pump of 6" water line connected to a header of 6 mtr long of 6" line, on this header the six tapping are connected, 4 nos. 3" line goes to 11 mtr height water cooler the pressure of the line is 0.15 to 0.25 kg/cm2, 2" and 4" pipe line connected to a cooler at 4 mtrlevel plateform. my question is, at 11 mtr height level the quantity of water and flow is not sufficient for my cooler, the temp. of cooler is rises much more. you are requested to suggest the modification of pipe line/ pump for take more water flow and pressure (desired pressure is 1 kg/cm2)
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Question 78 - Fact 1 : Dry air contains 20.95 % oxygen, 78.09 % nitrogen, 0.93 % argon, 0.039% carbon dioxide, and small amounts of other gases by volume. Fact 2 : Volume occupied is directly proportional to the number of moles for ideal gases at constant temperature and pressure. Fact 3 : 12.5 moles of pure oxygen is required to completely burn 1 mole of pure octane. Fact 4 : Air–fuel ratio (AFR) is the mass ratio of dry air to fuel present in a combustion process such as in an internal combustion engine or industrial furnace. Fact 5 : Molecular weight of oxygen gas is 31.998 g / mole and molecular weight of nitrogen gas is 28.014 g / mole. (a) Find the molar ratio of nitrogen and oxygen, or (moles of nitrogen) / (moles of oxygen) in dry air, by assuming ideal features of nitrogen and oxygen gases. (b) How many moles of nitrogen are available if dry air is used to completely burn the 1 mole pure octane? (c) Find the mass of fuel of 1 mole of octane with molecular weight of 114.232 g / mole. (d) Find the mass of dry air with 12.5 moles of pure oxygen by assuming only oxygen and nitrogen gases exist in the air. (e) Find the air-fuel ratio (AFR) when octane is used as fuel. (f) Find the fuel-air ratio (FAR) when octane is used as fuel.
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