Answer / sandeep prabha

any clu... Thanks in advance

Answer / dharannya

Basic separately excited motor equations are

V=E+Ia*Ra-------------(1)
E=K*W-----------------(2)
T=K*Ia----------------(3)

from the first set of data ie Ra=2, Ia=10 T=20,
and from equation (3)
20=K*10
therefore K=2.

with this knowledge of K
continuing to 2nd set of data ie V=100 and T=10
again from eqn(3) we get Ia as 5A

knowing Ia Ra and V from eqn (1) we get E as 90V

from eqn(2) knowing the values of E and K we obtain w(omega,
ie speed) as 45 rad/sec or 416.67 rpm

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