#define CUBE(x) (x*x*x) main() { int a,b=3; a=cube(b++); printf("%

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Question

#define CUBE(x) (x*x*x)
main()
{ int a,b=3;
a=cube(b++);
printf("%d %d",a,b);
}
  What should be the value of a and b? My calc a=4 but syst 
a=6 how pls tell me if you know it?

Question Submitted By :: B.sudharsan

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Answer Posted By

Re: #define CUBE(x) (x*x*x) main() { int a,b=3; a=cube(b++); printf("%d %d",a,b); } What should be the value of a and b? My calc a=4 but syst a=6 how pls tell me if you know it?

Answer
# 1

surely 'a' cannot be 4 or 6.... it will be the value of b... since we are multiplying b++ thrice...... so surely 'a' cannot be 4 or 6.....

according to me  b=6 , and a=60......


thank u

Is This Answer Correct ?

0 Yes

1 No

Vignesh1988i

Re: #define CUBE(x) (x*x*x) main() { int a,b=3; a=cube(b++); printf("%d %d",a,b); } What should be the value of a and b? My calc a=4 but syst a=6 how pls tell me if you know it?

Answer
# 2

27 4 is the output.
 
the call to the macro sets a = b*b*b with b = 3, 3 cubed is 27
then b is incremented to 4 after the macro call

Is This Answer Correct ?

3 Yes

0 No

P. Smith

Question	Asked @	Answers
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